On the Diophantine Equation (2x-1) (3y-1) =2z2
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摘要: 当2×x时,利用初等方法证明了丢番图方程(2x-1)(3y-1)=2z2只有正整数解(x,y,z)=(1,1,1),(1,5,11),(1,2,2).
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引用本文: | 佟瑞洲. 关于丢番图方程(2x-1)(3y-1)=2z2[J]. 上海工程技术大学学报, 2019, 33(3): 283-284,288. doi: 10.3969/j.issn.1009-444X.2019.03.017 |
Citation: | TONG Ruizhou. On the Diophantine Equation (2x-1) (3y-1) =2z2[J]. Journal of Shanghai University of Engineering Science, 2019, 33(3): 283-284,288. doi: 10.3969/j.issn.1009-444X.2019.03.017 |